after4D before4D compareFloat8 compareInt4 compareTimestampTz contain4D distance_tbox_nodebox getQuadrant4D left4D overAfter4D overBefore4D overlap4D overLeft4D overRight4D right4D SortedTbox Tbox_kdtree_choose Tbox_kdtree_inner_consistent Tbox_kdtree_picksplit tbox_level_cmp Tbox_quadtree_choose Tbox_quadtree_inner_consistent Tbox_quadtree_picksplit Tbox_spgist_config tbox_spgist_inner_consistent Tbox_spgist_leaf_consistent tbox_tmax_cmp tbox_tmin_cmp tbox_xmax_cmp tbox_xmin_cmp tboxnode_copy tboxnode_init tboxnode_kdtree_next tboxnode_quadtree_next Tnumber_spgist_compress tnumber_spgist_get_tbox

left4D() static bool left4D ( const TboxNode *  nodebox, const TBox *  query  ) static Can any box from nodebox be to the left of the query? A span s1 is to the left of a span s2 if s1.upper < s2.lower. Therefore, given a query box and a node box, a box in the node box may may be to the left of the query box if for dimension X nodebox->right.span.upper (the maximum of the upper bounds in the node box) < query->span.lower (the lower bound of the query). Continuing with the example at the top of this file, if TboxNode is left = TBOXFLOAT XT([3, 7],[2001-01-03, 2001-01-07]) right = TBOXFLOAT XT([5, 9],[2001-01-05, 2001-01-09]) a query `TBOXFLOAT XT([10, 12],[2001-01-10, 2001-01-12]) satisfies the above condition.